# Line slope calculator x+5y=13

**Straight line given by points A[3; 2] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.2x+2.6

**Canonical form of the line equation:**x+5y-13 = 0

**Parametric form of the line equation:**

x = 5t+3

y = -t+2 ; t ∈ R

**Slope:**m = -0.2

**Slope angle of line: φ =**-11°18'36″ = -0.1974 rad

**X intercept:**x

_{0}= 13

**Y intercept:**y

_{0}= q = 2.6

**Distance line from the origin:**d

_{0}= 2.5495

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; -1)

**Normal vector: n =**(1; 5)

**Midpoint of the segment AB: M =**[5.5; 1.5]

**Perpendicular Bisector equation:**5x-y-26 = 0

**Vector OA = (3; 2) ; |OA| = 3.6056**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 26**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**