# Line slope calculator 8x-y=38

**Straight line given by points A[5; 2] and B[6; 10]**

## Calculation:

**Slope-intercept form of line:**y = 8x-38

**Canonical form of the line equation:**8x-y-38 = 0

**Parametric form of the line equation:**

x = t+5

y = 8t+2 ; t ∈ R

**Slope:**m = 8

**Slope angle of line: φ =**82°52'30″ = 1.4464 rad

**X intercept:**x

_{0}= 4.75

**Y intercept:**y

_{0}= q = -38

**Distance line from the origin:**d

_{0}= 4.7133

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(1; 8)

**Normal vector: n =**(8; -1)

**Midpoint of the segment AB: M =**[5.5; 6]

**Perpendicular Bisector equation:**x+8y-53.5 = 0

**Vector OA = (5; 2) ; |OA| = 5.3852**

**Vector OB = (6; 10) ; |OB| = 11.6619**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 37°14'5″ = 0.6499 rad**